Worked example

Solve the inequality |xβˆ’5| < 3|2x+2|

A-Level Maths Β· 97094 marksmed
Question

Solve the inequality .

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Full worked solution

  1. Eliminate absolute value signs by squaring

    Since all absolute value expressions are non-negative for all real , we can square both sides of the inequality without changing its direction, using the identity for all real .

    (xβˆ’5)2<(3∣2x+2∣)2(x - 5)^2 < \left(3|2x + 2|\right)^2

    Simplify the right-hand side, expand both sides, and rearrange all terms to one side of the inequality:

    (xβˆ’5)2<9(2x+2)2 x2βˆ’10x+25<9(4x2+8x+4) x2βˆ’10x+25<36x2+72x+36 0<35x2+82x+11(x - 5)^2 < 9(2x + 2)^2 \ x^2 - 10x + 25 < 9(4x^2 + 8x + 4) \ x^2 - 10x + 25 < 36x^2 + 72x + 36 \ 0 < 35x^2 + 82x + 11

    We now have the standard quadratic inequality .

    Note.

    Squaring both sides is only safe when both sides are non-negative, which is always true for absolute value expressions. Never square an inequality with unknown signs on either side.

  2. Find critical values by solving the quadratic equation

    First solve the corresponding quadratic equation using the quadratic formula , where , , and . First calculate the discriminant:

    Ξ”=b2βˆ’4ac=822βˆ’4(35)(11)=6724βˆ’1540=5184=722\Delta = b^2 - 4ac = 82^2 - 4(35)(11) = 6724 - 1540 = 5184 = 72^2

    Now compute the roots:

    x=βˆ’82Β±722(35)=βˆ’82Β±7270x = \frac{-82 \pm 72}{2(35)} = \frac{-82 \pm 72}{70}

    First root: Second root: The critical values are (or ) and (or approximately ).

    Note.

    The quadratic formula works for all quadratic equations, so it is a reliable method to find critical points even when factoring is not obvious.

  3. Determine the solution interval from the quadratic graph

    The quadratic function has a positive leading coefficient, so its graph is an upward-opening parabola that crosses the -axis at the critical points and . An upward-opening parabola is above the -axis (i.e. ) outside the interval between its two roots.

Answer

or

What this tests

  • Absolute value identities
  • Quadratic inequality solving
  • Graphical interpretation of quadratic functions
  • Quadratic formula application
⚠️

⚠ A common mistake is incorrectly rearranging the inequality after squaring, leading to a wrong sign on the leading coefficient of the quadratic, which flips the solution interval. Always double-check your rearrangement steps.

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