Study Guide

E.6 Fission and fusion (AHL)

IB Physics HLΒ· 45 min read

1. Energy Release from Fission and Fusionβ˜…β˜…β˜†β˜†β˜†β± 15 min

Both processes release energy because of the shape of the binding energy per nucleon (BE/A) curve. Intermediate mass nuclei (A β‰ˆ 56) have the highest BE/A, so splitting heavy nuclei (fission) or joining light nuclei (fusion) produces more tightly bound products, with excess energy released.

πŸ“˜ Definition

Mass-Energy Equivalence

The energy released in a nuclear reaction is equal to the mass defect multiplied by the speed of light squared.

Example:

A mass defect of 1 u corresponds to 931.5 MeV of released energy

E=Ξ”mc2whereΞ”m=mreactantsβˆ’mproductsE = \Delta m c^2 \quad \text{where} \quad \Delta m = m_{\text{reactants}} - m_{\text{products}}
πŸ“ Worked Example

Calculate the energy released in the fission reaction: . Given masses: u, u, u, u. 1 u = 931.5 MeV/cΒ².

  1. 1

    Calculate total mass of reactants:

    mreactants=235.0439+1.0087=236.0526 um_{\text{reactants}} = 235.0439 + 1.0087 = 236.0526 \text{ u}
  2. 2

    Calculate total mass of products:

    mproducts=140.9144+91.9262+(3Γ—1.0087)=235.8667 um_{\text{products}} = 140.9144 + 91.9262 + (3 \times 1.0087) = 235.8667 \text{ u}
  3. 3

    Find the positive mass defect:

    Ξ”m=236.0526βˆ’235.8667=0.1859 u\Delta m = 236.0526 - 235.8667 = 0.1859 \text{ u}
  4. 4

    Convert mass defect to energy released:

    E=0.1859Γ—931.5β‰ˆ173 MeVE = 0.1859 \times 931.5 \approx 173 \text{ MeV}

2. Nuclear Fission and Chain Reactionsβ˜…β˜…β˜†β˜†β˜†HL only⏱ 20 min

When a heavy fissile nucleus absorbs a neutron and undergoes fission, it releases multiple new neutrons. These neutrons can trigger fission in other nearby nuclei, creating a multiplying chain reaction.

πŸ“˜ Definition

Critical Chain Reaction

A steady chain reaction where exactly one neutron from each fission event goes on to cause another fission, maintaining constant power output.

In commercial nuclear reactors, neutron-absorbing control rods (made of boron or cadmium) are adjusted to maintain a critical state. Subcritical reactions (k < 1) die out, while supercritical reactions (k > 1) grow exponentially.

πŸ“ Worked Example

A reactor starts with 1 neutron in generation 1. The neutron multiplication factor . How many neutrons are present in generation 100?

  1. 1

    The number of neutrons after generations follows the exponential growth rule:

    Nn=knβˆ’1N_n = k^{n-1}
  2. 2

    Substitute and :

    N100=(1.01)99β‰ˆ2.7N_{100} = (1.01)^{99} \approx 2.7
  3. 3

    Interpret the result: the number of neutrons slowly increases, so control rods must be adjusted to reduce to 1 for steady power.

3. Nuclear Fusionβ˜…β˜…β˜…β˜†β˜†HL only⏱ 20 min

Nuclear fusion joins two light positively charged nuclei to form a heavier nucleus. For fusion to occur, the nuclei must overcome electrostatic Coulomb repulsion between them, which requires extremely high temperatures (β‰₯ 10⁷ K) and high density to produce frequent energetic collisions.

πŸ“˜ Definition

Coulomb Repulsion

The electrostatic force that repels two positively charged atomic nuclei, which must be overcome for fusion to occur.

πŸ“ Worked Example

Calculate the energy released in the deuterium-tritium fusion reaction: . Given masses: u, u, u, u.

  1. 1

    Calculate total mass of reactants:

    mreactants=2.0141+3.0160=5.0301 um_{\text{reactants}} = 2.0141 + 3.0160 = 5.0301 \text{ u}
  2. 2

    Calculate total mass of products:

    mproducts=4.0026+1.0087=5.0113 um_{\text{products}} = 4.0026 + 1.0087 = 5.0113 \text{ u}
  3. 3

    Calculate energy released:

    E=(5.0301βˆ’5.0113)Γ—931.5β‰ˆ17.5 MeVE = (5.0301 - 5.0113) \times 931.5 \approx 17.5 \text{ MeV}

4. Exam Command Term Guidanceβ˜…β˜…β˜†β˜†β˜†β± 10 min

5. Common Pitfalls

Wrong move:

Calculating mass defect as product mass minus reactant mass

Why:

This gives a negative Ξ”m, which can lead to confusion and lost marks for exothermic reactions

Correct move:

Always calculate Ξ”m = m_reactants - m_products to get a positive value for energy released

Wrong move:

Claiming fusion releases more energy per reaction than fission

Why:

Per individual reaction, fission releases ~170-200 MeV, while fusion releases ~10-20 MeV

Correct move:

State that fusion releases more energy per unit mass of fuel, not per reaction

Wrong move:

Confusing critical, subcritical and supercritical chain reaction states

Why:

Students often mix up the value of the multiplication factor k for each state

Correct move:

k<1 = subcritical (dies out), k=1 = critical (steady), k>1 = supercritical (grows)

Wrong move:

Thinking the Sun's core is hotter than fusion reactors on Earth

Why:

The Sun has extremely high core pressure, so fusion proceeds at lower temperatures than Earth-based reactors

Correct move:

Remember Earth fusion reactors need higher temperatures to compensate for lower pressure

6. Quick Reference Cheatsheet

Property

Nuclear Fission

Nuclear Fusion

Reactant nuclei

Heavy (A > 200)

Light (A < 20)

Energy per reaction

~170-200 MeV

~10-20 MeV

Energy per kg fuel

~8 Γ— 10ΒΉΒ³ J

~3 Γ— 10¹⁴ J (4Γ— fission)

Required conditions

Critical mass of fissile material

T > 10⁷ K, plasma confinement

Waste

Long-lived highly radioactive waste

Low-level short-lived waste

Commercial use

Mature technology

Still in development

7. Frequently Asked

Why does fusion release more energy per kg than fission?

Fusion of light nuclei produces a larger increase in binding energy per nucleon per unit mass than fission of heavy nuclei, leading to ~3-4 times more energy released per kilogram of fuel.

When this came up on past exams

AI-estimated based on syllabus patterns β€” cross-check with official past papers for accuracy. Use only as revision-focus signals.

  • 2025 Β· 2

    Energy calculation for deuterium fusion

  • 2023 Β· 1

    Fission chain reaction control explanation

  • 2021 Β· 2

    Compare fission and fusion fuel properties

Going deeper

What's Next

This topic builds on your understanding of binding energy and mass defect to explain two of the most important energy-releasing nuclear processes in physics. Mastery of fission and fusion is essential for understanding stellar evolution, nucleosynthesis, and nuclear energy production, which are common long-answer topics in IB Physics HL exams. The concepts here also connect directly to real-world energy debates and modern physics research into sustainable power. Below are related topics to explore next to deepen your understanding.