Study Guide

Arithmetic sequences and series

IB Mathematics: Applications and Interpretation SLΒ· 5 min read

1. What is an Arithmetic Sequence?β˜…β˜†β˜†β˜†β˜†β± 10 min

πŸ“˜ Definition

Arithmetic Sequence

= nth term, = first term, = common difference

A sequence where the difference between every pair of consecutive terms is constant. This constant is called the common difference.

Example:

3, 7, 11, 15... has ,

To confirm a sequence is arithmetic, you just calculate the difference between each pair of consecutive terms. If all differences are equal, the sequence is arithmetic. If any difference differs, the sequence is not arithmetic.

πŸ“ Worked Example

Is 2, 5, 8, 11, 15 an arithmetic sequence?

  1. 1

    Calculate the difference between the second and first term:

    5βˆ’2=35 - 2 = 3
  2. 2

    Calculate the difference between the third and second term:

    8βˆ’5=38 - 5 = 3
  3. 3

    Calculate the difference between the fourth and third term:

    11βˆ’8=311 - 8 = 3
  4. 4

    Calculate the difference between the fifth and fourth term:

    15βˆ’11=415 - 11 = 4
  5. 5

    The differences are not all equal, so the sequence is not arithmetic.

Exam tip:

Always check at least three consecutive difference values to confirm a sequence is arithmetic.

2. The General nth Term Formulaβ˜…β˜…β˜†β˜†β˜†β± 15 min

We can derive a general formula for the nth term by starting from the definition: the first term is , the second term is , the third term is , and so on. To get the nth term, we add a total of times to the first term.

un=u1+(nβˆ’1)du_n = u_1 + (n-1)d
πŸ“ Worked Example

Find the 20th term of the arithmetic sequence 5, 9, 13, 17...

  1. 1

    Identify the required parameters:

    u1=5,d=9βˆ’5=4,n=20u_1 = 5, \quad d = 9 - 5 = 4, \quad n = 20
  2. 2

    Substitute into the nth term formula:

    u20=5+(20βˆ’1)(4)u_20 = 5 + (20 - 1)(4)
  3. 3

    Simplify to get the final result:

    u20=5+19Γ—4=5+76=81u_20 = 5 + 19 \times 4 = 5 + 76 = 81
  4. 4

    Final answer: The 20th term is 81.

βœ“ Quick check

Test your understanding

  1. What is the 12th term of the sequence 100, 92, 84...?

    • 12

    • 8

    • -8

    • -12

    Reveal answer
    12 β€”

    Correct: , , so

3. Sum of an Arithmetic Seriesβ˜…β˜…β˜†β˜†β˜†β± 15 min

πŸ“˜ Definition

Arithmetic Series

SnS_n

The sum of the first n terms of an arithmetic sequence, denoted

The sum formula comes from pairing the first and last term: every pair adds up to the same value of , and there are such pairs. There are two equivalent forms of the formula.

Sn=n2(u1+un)S_n = \frac{n}{2} (u_1 + u_n)
Sn=n2[2u1+(nβˆ’1)d]S_n = \frac{n}{2} \left[ 2u_1 + (n-1)d \right]
πŸ“ Worked Example

Find the sum of the first 30 terms of the sequence 2, 6, 10, 14...

  1. 1

    Identify parameters:

    u1=2,d=4,n=30u_1 = 2, \quad d = 4, \quad n = 30
  2. 2

    Use the formula with and , since we do not know :

    S30=302[2(2)+(30βˆ’1)(4)]S_30 = \frac{30}{2} \left[ 2(2) + (30 - 1)(4) \right]
  3. 3

    Simplify step by step:

    S30=15[4+116]=15Γ—120=1800S_30 = 15 \left[ 4 + 116 \right] = 15 \times 120 = 1800
  4. 4

    Final answer: The sum of the first 30 terms is 1800.

Exam tip:

If you know both the first and last term, use the first sum formula for faster calculation in exams.

4. Real-World Applicationsβ˜…β˜…β˜…β˜†β˜†β± 15 min

IB AI SL exams regularly test arithmetic sequences in real contexts, including fixed monthly savings increments, simple interest, and constant annual depreciation of assets. The key skill is translating the word problem into sequence parameters correctly.

πŸ“ Worked Example

A person saves $100 in the first month, and increases their savings by $20 each month. What is their total savings after 12 months?

  1. 1

    Translate to sequence parameters: first month savings is , monthly increment is , number of months is :

    u1=100,d=20,n=12u_1 = 100, \quad d = 20, \quad n = 12
  2. 2

    Total savings is the sum of the first 12 terms, so substitute into the sum formula:

    S12=122[2(100)+(12βˆ’1)(20)]S_12 = \frac{12}{2} \left[ 2(100) + (12 - 1)(20) \right]
  3. 3

    Simplify:

    S12=6[200+220]=6Γ—420=2520S_12 = 6 \left[ 200 + 220 \right] = 6 \times 420 = 2520
  4. 4

    Final answer: Total savings after 12 months is $2520.

5. Common Pitfalls

Wrong move:

Using instead of in the nth term and sum formulas

Why:

There are only common differences between the first term and the nth term, so using gives an incorrect result

Correct move:

Always write in both formulas, double-check this before substituting values

Wrong move:

Using a positive for decreasing sequences

Why:

If the sequence decreases, the difference between consecutive terms is negative

Correct move:

Always calculate as to automatically get the correct sign

Wrong move:

Miscalculating when summing from term m to term k

Why:

Counting terms skips the starting term m

Correct move:

For inclusive counting, use to get the correct number of terms

Wrong move:

Confusing the nth term formula with the sum formula

Why:

Exam questions often ask for either a single term or a total sum, mixing up formulas leads to losing easy marks

Correct move:

Underline what the question asks for: "find the 10th term" = nth term formula, "find the total of 10 terms" = sum formula

Wrong move:

Assuming a sequence is arithmetic without checking

Why:

Exam questions sometimes give geometric sequences to test if you check for constant difference

Correct move:

Always check the difference between at least two pairs of consecutive terms before proceeding

6. Quick Reference Cheatsheet

Concept

Formula

Key Notes

nth term

Sum (know )

Fastest for this case

Sum (know )

Use when you don't know

Number of terms (m to k)

Add 1 for inclusive counting

When this came up on past exams

AI-estimated based on syllabus patterns β€” cross-check with official past papers for accuracy. Use only as revision-focus signals.

  • 2022 Β· 1

    4 mark real-world sequence problem

  • 2023 Β· 2

    6 mark cumulative savings problem

  • 2021 Β· 1

    3 mark nth term calculation

Going deeper

What's Next

Arithmetic sequences and series are the foundational discrete sequence type you will use throughout IB AI SL. They share a similar structure to geometric sequences and series, which are the other core sequence type tested on the exam. The logic of fixed constant increments also translates directly to linear growth models, linear regression, and financial applications you will cover later in the course. Mastery of this topic makes learning more advanced sequence and modelling topics much simpler.