Study Guide

Quadratic functions, roots and discriminant

IB Mathematics: Analysis and Approaches SLΒ· Unit 2: Functions, Topic 2.5Β· 15 min read

1. Roots and the discriminant: Key definitionβ˜…β˜…β˜†β˜†β˜†β± 5 min

πŸ“˜ Definition

Discriminant

For a quadratic equation in standard form where , the discriminant is the value calculated from coefficients that tells us the nature of the roots, with formula .

Example:

For , .

Roots of the quadratic equation are the x-values that satisfy the equation. These correspond exactly to the x-intercepts of the quadratic function .

πŸ“ Worked Example

Calculate the discriminant of the quadratic equation .

  1. 1

    First, identify coefficients from the standard form :

  2. 2
    a=3,b=2,c=βˆ’4a = 3, \quad b = 2, \quad c = -4
  3. 3

    Substitute into the discriminant formula to calculate :

  4. 4
    Ξ”=(2)2βˆ’4(3)(βˆ’4)=4+48=52\Delta = (2)^2 - 4(3)(-4) = 4 + 48 = 52

2. Interpreting the discriminant: Nature of rootsβ˜…β˜…β˜†β˜†β˜†β± 5 min

The value of the discriminant tells us how many real roots (and how many x-intercepts) the quadratic has. IB AA SL only works with real roots, so we have three distinct cases:

  • If : Two distinct real roots β†’ two distinct x-intercepts

  • If : One repeated (equal) real root β†’ parabola touches the x-axis at exactly one point (the vertex lies on the x-axis)

  • If : No real roots β†’ parabola never intersects the x-axis, all function values have the same sign as

πŸ“ Worked Example

The quadratic function is . Determine how many x-intercepts it has.

  1. 1

    To find x-intercepts, set to get the quadratic equation:

  2. 2
    x2βˆ’4x+5=0x^2 - 4x + 5 = 0
  3. 3

    Calculate the discriminant:

  4. 4
    a=1,b=βˆ’4,c=5Ξ”=(βˆ’4)2βˆ’4(1)(5)=16βˆ’20=βˆ’4a = 1, \quad b = -4, \quad c = 5 \\ \Delta = (-4)^2 - 4(1)(5) = 16 - 20 = -4
  5. 5

    Interpret the result to get the answer:

  6. 6
    Ξ”<0β€…β€ŠβŸΉβ€…β€Š0 real roots, so 0 x-intercepts\Delta < 0 \implies \text{0 real roots, so 0 x-intercepts}

3. Applying the discriminant to problems with unknown coefficientsβ˜…β˜…β˜…β˜†β˜†β± 5 min

The most common exam question on this topic gives a quadratic with an unknown constant (usually called ) and a condition on the roots, then asks for possible values of . The method is always the same: write in terms of the unknown, apply the condition for , then solve the resulting equation or inequality.

πŸ“ Worked Example

Find the range of values of for which has two distinct real roots.

  1. 1

    Identify coefficients in terms of :

  2. 2
    a=1,b=2k,c=9a = 1, \quad b = 2k, \quad c = 9
  3. 3

    Calculate the discriminant and simplify:

  4. 4
    Ξ”=(2k)2βˆ’4(1)(9)=4k2βˆ’36\Delta = (2k)^2 - 4(1)(9) = 4k^2 - 36
  5. 5

    Apply the condition for two distinct real roots, which requires :

  6. 6
    4k2βˆ’36>0k2βˆ’9>0(kβˆ’3)(k+3)>04k^2 - 36 > 0 \\ k^2 - 9 > 0 \\ (k - 3)(k + 3) > 0
  7. 7

    Solve the inequality to get the final solution:

  8. 8
    k<βˆ’3 or k>3k < -3 \text{ or } k > 3
βœ“ Quick check

Check your understanding:

  1. What is the correct condition for the parabola (with ) to always lie above the x-axis?

    Reveal answer
    $\Delta < 0$ β€”

    Correct! If the parabola opens upwards, and if it never crosses the x-axis, so it is always above the x-axis.

4. Common Pitfalls

Wrong move:

Taking c with the wrong sign after rearranging the quadratic to equal zero

Why:

Sign errors are the most common mistake in discriminant calculations. A negative c flips the sign of the term.

Correct move:

Always rearrange the equation to first, then write down a, b, c including their explicit signs before calculating .

Wrong move:

Stating gives two real roots

Why:

gives one repeated (equal) root, not two distinct roots. This is a common marked error in exams.

Correct move:

Use the phrasing "one repeated real root" or "one real root" when .

Wrong move:

Writing for two distinct roots, or for at least one real root

Why:

Wording of the question directly defines the required inequality. Mismatching the inequality loses easy marks.

Correct move:

Match the condition exactly: two distinct roots β†’ , at least one real root β†’ .

Wrong move:

Forgetting to check the leading coefficient is not zero when it is unknown

Why:

If the coefficient of is unknown, a value that makes it zero gives a linear equation, not a quadratic, changing the number of roots.

Correct move:

Always confirm first when the leading coefficient contains an unknown constant.

Wrong move:

Miscalculating when c is negative: e.g. , writing

Why:

Double negative multiplication errors are extremely common in discriminant calculations.

Correct move:

Double-check the sign of the term: negative Γ— negative = positive.

5. Quick Reference Cheatsheet

Discriminant value

Number of real roots

Number of x-intercepts

Graph description

2 distinct

2

Crosses x-axis at two points

1 repeated

1

Touches x-axis at vertex

0

0

Never crosses the x-axis

When this came up on past exams

AI-estimated based on syllabus patterns β€” cross-check with official past papers for accuracy. Use only as revision-focus signals.

  • 2022 Β· 1

    Find k for two distinct real roots

  • 2023 Β· 2

    Determine number of x-intercepts

  • 2021 Β· 1

    Find k for repeated root

Going deeper

What's Next

Mastering discriminant and roots of quadratics is a foundational skill that extends to almost all other algebra and geometry topics in IB AA SL. You will use these exact same ideas when finding intersections between lines and curves: you set the equations equal to get a quadratic, then use the discriminant to find how many intersection points exist. This is a very common question in coordinate geometry and tangent problems. You will also extend these concepts to higher-order polynomials when working with cubic and quartic functions later in the course. Building fluency with the discriminant now will help you avoid simple errors in these more complex problems.