Study Guide

Movement of substances into and out of cells

BiologyΒ· 2.15–2.17 (Issue 3 spec)Β· 25 min read

1. Core Cell Transport Processes (2.15)β˜…β˜…β˜†β˜†β˜†β± 8 min

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πŸ“˜ Definition

Diffusion

Net movement of particles from a region of higher concentration to a region of lower concentration (down a concentration gradient), no energy required (passive process)

πŸ“˜ Definition

Osmosis

Net movement of water molecules from a region of higher water concentration (dilute solution) to a region of lower water concentration (concentrated solution) across a partially permeable membrane, passive process

πŸ“˜ Definition

Active Transport

Movement of substances against a concentration gradient (from lower to higher concentration), requires energy released from respiration, uses carrier proteins in the cell membrane

πŸ“ Worked Example

A student defines osmosis as 'the diffusion of water from a dilute solution to a concentrated solution'. State one missing element of this definition required for full marks.

  1. 1

    Step 1: Recall Edexcel's mandatory requirements for osmosis definitions.

  2. 2

    Step 2: Identify that the definition mentions water movement and concentration direction, but omits the critical partially permeable membrane requirement.

  3. 3

    Answer: The definition does not state that osmosis occurs across a partially permeable membrane.

2. Factors Affecting Transport Rate (2.16)β˜…β˜…β˜…β˜†β˜†β± 7 min

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Four key factors affect how quickly substances move into or out of cells, all assessed regularly in exam questions:

  • Concentration gradient steepness: The steeper the difference in concentration between two regions, the faster the rate of diffusion and osmosis.

  • Temperature: Higher temperatures give particles more kinetic energy, so they move faster, increasing transport rate.

  • Diffusion pathway distance: The shorter the distance particles have to travel, the faster the rate of transport.

  • Surface area to volume ratio (SA:V): Smaller cells/organisms have a larger surface area relative to their volume, so exchange of substances happens faster. Larger organisms require specialized exchange surfaces to compensate for their small SA:V.

πŸ“ Worked Example

Explain why a mouse has a faster rate of gas exchange per gram of body mass than an elephant.

  1. 1

    Step 1: Link organism size to surface area to volume ratio.

  2. 2

    Step 2: A mouse is much smaller than an elephant, so it has a far higher surface area to volume ratio.

  3. 3

    Step 3: A higher SA:V means more surface area is available for gas exchange per gram of body mass, leading to faster exchange rates.

3. Required Practical: Diffusion and Osmosis (2.17)β˜…β˜…β˜…β˜†β˜†β± 7 min

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You will be assessed on your understanding of both living (e.g. potato tissue) and non-living (e.g. agar, Visking tubing) practical investigations of diffusion and osmosis.

For the common potato osmosis practical: potato cores are cut to equal size, blotted dry, weighed, then placed in solutions of varying sugar/salt concentration for a fixed time, then re-blotting and re-weighing to calculate percentage change in mass.

  • Mass/length increase: Net movement of water into potato cells, so the external solution is more dilute than potato cell sap. Cells become turgid.

  • Mass/length decrease: Net movement of water out of potato cells, so the external solution is more concentrated than potato cell sap. Cells become flaccid or plasmolysed.

  • No change in mass/length: The external solution has the same concentration as the potato cell sap, so there is no net movement of water.

πŸ“ Worked Example

A potato core placed in a 0.5M sucrose solution loses 8% of its mass. Explain this result.

  1. 1

    Step 1: Link mass loss to water movement via osmosis.

  2. 2

    Step 2: The 0.5M sucrose solution is more concentrated than the potato cell sap, so water moves out of the potato cells across their partially permeable cell membranes.

  3. 3

    Step 3: The net loss of water from the potato cells causes the core to decrease in mass.

4. Comparing Passive and Active Transportβ˜…β˜…β˜†β˜†β˜†β± 3 min

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Feature

Diffusion

Osmosis

Active Transport

Energy required?

No (passive)

No (passive)

Yes (from respiration)

Gradient direction

Down (high→low)

Down (high→low water)

Against (low→high)

Partially permeable membrane required?

No

Yes

No (uses carrier proteins)

Substances transported

Small soluble particles (Oβ‚‚, glucose)

Water only

Ions, large molecules (minerals)

βœ“ Quick check
  1. Which process requires energy from respiration to move substances against a concentration gradient?

    • Diffusion

    • Osmosis

    • Active transport

    Reveal answer
    2 β€”

    Active transport is the only active process listed, using energy from respiration to move substances up a concentration gradient.

5. Common Pitfalls

Wrong move:

Defining osmosis as 'diffusion of water' without mentioning a partially permeable membrane

Why:

Edexcel marking schemes explicitly require reference to the membrane for full marks, this is a common discriminator question

Correct move:

Always include 'across a partially permeable membrane' in any osmosis definition

Wrong move:

Stating active transport uses energy from the concentration gradient

Why:

Active transport moves against the gradient, so it cannot use gradient energy

Correct move:

Explicitly state active transport uses energy released from aerobic respiration

Wrong move:

Mixing up water movement direction in osmosis practicals

Why:

Many students mix up dilute/concentrated solutions and mass change, losing marks in practical interpretation questions

Correct move:

Remember water moves to the more concentrated solution: if external solution is more concentrated than cells, water leaves and mass decreases

Wrong move:

Stating larger organisms have a larger surface area to volume ratio

Why:

SA:V decreases as organism size increases, a common multiple choice misconception

Correct move:

Smaller cells/organisms have higher SA:V, larger ones have lower SA:V

Wrong move:

Using absolute mass change instead of percentage change for practical comparisons

Why:

Starting masses of potato cores are never identical, so absolute change does not allow fair comparison

Correct move:

Calculate percentage change in mass using % change = ((final mass - initial mass)/initial mass) Γ— 100

6. Quick Reference Cheatsheet

Term

Exam-Ready Key Definition

Diffusion

Net movement of particles down concentration gradient, passive, no energy

Osmosis

Net movement of water down water concentration gradient, across partially permeable membrane, passive

Active Transport

Movement against concentration gradient, uses energy from respiration

Rate Factors

SA:V, temperature, concentration gradient, diffusion distance

Practical Rule

Mass ↑ = water in (external dilute), mass ↓ = water out (external concentrated)

7. Frequently Asked

Can I call osmosis 'diffusion of water' in exams?

No. Edexcel marking schemes require you to explicitly mention that osmosis occurs across a partially permeable membrane alongside the net movement of water down a water concentration gradient to get full marks.

What energy source does active transport use?

Active transport uses energy released from aerobic respiration in cells, not energy from the concentration gradient like passive transport processes.

Going deeper

What's Next

Now that you have mastered core cell transport processes, you can apply this foundational knowledge to specialized exchange surfaces and transport systems across living organisms, a frequent topic in Edexcel IGCSE Biology exam papers. You will encounter diffusion in gas exchange systems in animals (alveoli) and plants (leaf stomata), osmosis in root hair cell water uptake, and active transport in mineral ion absorption in plant roots and nutrient uptake in the small intestine villi. Be sure to practice past paper questions on this topic to familiarize yourself with strict marking scheme requirements, especially for definition and practical interpretation questions, which are common high-mark questions across both Paper 1 and Paper 2.