Study Guide

Newton's laws of motion

CIE A-Level PhysicsΒ· Unit 3: DynamicsΒ· 15 min read

1. Newton's First Law of Motionβ˜…β˜…β˜†β˜†β˜†β± 5 min

πŸ“˜ Definition

Newton's First Law

Fnet=0F_{net} = 0

A body will remain at rest, or continue to move at a constant velocity, unless acted upon by a resultant external force.

Example:

An ice puck sliding on a frictionless surface maintains constant speed.

πŸ“ Worked Example

A truck travels at constant speed of 22 m/s along a straight horizontal road. The engine provides a driving force of 8500 N. What is the total resistive force acting on the truck?

  1. 1
    1. Constant speed in a straight line means constant velocity, so per Newton's First Law, the resultant net force on the truck is zero.
  2. 2
    1. Sum of forces: driving force minus total resistive force equals zero:
  3. 3
    Fdrivingβˆ’Fresistive=0F_{driving} - F_{resistive} = 0
  4. 4
    1. Solve for resistive force:
  5. 5
    Fresistive=Fdriving=8500 NF_{resistive} = F_{driving} = 8500 \text{ N}
  6. 6

    The resistive force acts opposite to the direction of motion.

Exam tip:

Always confirm both speed AND direction are constant before concluding net force is zero

2. Newton's Second Law of Motionβ˜…β˜…β˜…β˜†β˜†β± 7 min

πŸ“˜ Definition

Newton's Second Law

Fnet=dpdt=maF_{net} = \frac{dp}{dt} = ma

The rate of change of momentum of a body is equal to the resultant force acting on it, and acts in the same direction as the resultant force.

Example:

For a 3 kg mass accelerating at 4 m/sΒ², net force is 3 Γ— 4 = 12 N.

πŸ“ Worked Example

A 4 kg block is pulled along a rough horizontal surface by a force of 25 N parallel to the surface. Friction opposes motion with magnitude 9 N. Calculate the acceleration of the block.

  1. 1
    1. Calculate the resultant force acting parallel to the surface:
  2. 2
    Fnet=25βˆ’9=16 NF_{net} = 25 - 9 = 16 \text{ N}
  3. 3
    1. Use Newton's Second Law for constant mass, , rearrange for acceleration:
  4. 4
    a=Fnetma = \frac{F_{net}}{m}
  5. 5
    1. Substitute values:
  6. 6
    a=164=4 m sβˆ’2a = \frac{16}{4} = 4 \text{ m s}^{-2}
βœ“ Quick check
  1. What is the net force on a 12 kg object accelerating at 2.5 m/sΒ²?

    • 14.5 N

    • 30 N

    • 4.8 N

    • 120 N

    Reveal answer
    30 N β€”

    Correct: N

3. Newton's Third Law of Motionβ˜…β˜…β˜…β˜†β˜†β± 6 min

πŸ“˜ Definition

Newton's Third Law

FAB=βˆ’FBAF_{AB} = -F_{BA}

If body A exerts a force on body B, then body B exerts a force of the same type that is equal in magnitude and opposite in direction on body A.

Example:

A bat exerts a force on a ball, the ball exerts an equal opposite force on the bat.

πŸ“ Worked Example

A person stands stationary on the ground. State one valid action-reaction pair in this system, and explain why the person's weight and the normal force from the ground are not a third law pair.

  1. 1
    1. One valid action-reaction pair is: (1) The Earth exerts a downward gravitational force (weight) on the person, (2) The person exerts an upward gravitational force of equal magnitude on the Earth.
  2. 2
    1. The weight of the person (gravity from Earth) and the normal force from the ground are not an action-reaction pair because: they act on the same body (the person) and are different types of force.
  3. 3

    Additionally, they do not have to be equal if the person is accelerating vertically (e.g. in an accelerating elevator).

Exam tip:

Always mention that action-reaction forces are the same type and act on different bodies in your exam answers.

4. Common Pitfalls

Wrong move:

Claiming balanced forces are an action-reaction pair per Newton's third law

Why:

Action-reaction pairs act on two different bodies, while balanced forces both act on the same body

Correct move:

Always check which body each force acts on, and confirm the two forces are the same type

Wrong move:

Using for systems with changing mass without adjusting for momentum change

Why:

only holds for constant mass; the general form of Newton's second law uses rate of change of momentum

Correct move:

Use for all problems, especially those with changing mass like rocket propulsion

Wrong move:

Calculating acceleration using only the applied force, forgetting to find the resultant net force

Why:

Newton's second law requires the sum of all forces, not just the single applied force you are given

Correct move:

Always sum all forces in the direction of motion to find before calculating acceleration

Wrong move:

Omitting the full statement of Newton's first law, calling it just a special case of the second law

Why:

Examiners require you to state all three laws separately when asked, and the first law defines inertial reference frames

Correct move:

Learn and write the full, complete statement of Newton's first law for exam responses

5. Quick Reference Cheatsheet

Law

Key Statement

Key Rule

First Law

Constant velocity if no resultant force

Second Law (constant mass)

Resultant force equals mass times acceleration

Second Law (general)

Resultant force equals rate of change of momentum

Third Law

Equal opposite forces on different bodies

Same force type, acts on two different objects

When this came up on past exams

AI-estimated based on syllabus patterns β€” cross-check with official past papers for accuracy. Use only as revision-focus signals.

  • 2023 Β· Paper 1

    Identify action-reaction pairs

  • 2022 Β· Paper 2

    Calculate acceleration from net force

  • 2021 Β· Paper 1

    Apply Newton's first law to constant motion

What's Next

Newton's laws of motion form the entire foundation of classical dynamics for CIE A-Level Physics, and underpin almost every topic that comes after this unit. Mastering the correct definition of each law and how to identify resultant forces is critical for solving all future force problems, from connected systems to circular motion and harmonic motion. This sub-topic also introduces momentum, which becomes a key tool for solving collisions and explosions problems. Below are the next key concepts you should study to build on this knowledge.