Study Guide

Mass, Weight and Density

Physics· 1.3, 1.4 (2026-2028 syllabus)· 15 min read

1. Mass vs Weight (Core)★☆☆☆☆⏱ 5 min

Mass is a measure of the amount of matter in an object, measured in kilograms (kg). It is a scalar quantity (magnitude only) and does not change with location. Weight is the force of gravity acting on an object, measured in newtons (N). It is a vector quantity (has magnitude and direction) and changes depending on local gravitational field strength.

📘 Definition

Weight

W=m×gW = m \times g

The gravitational force acting on an object, equal to the product of its mass and local gravitational field strength.

Example:

A 5kg mass on Earth (g=9.8N/kg) has a weight of 49N.

📐 Worked Example

Calculate the weight of a 2.5kg bag of flour on Earth, where g = 9.8 N/kg. State the unit of your answer.

  1. 1

    Step 1: Recall the weight formula

    W=m×gW = m \times g
  2. 2

    Step 2: Substitute given values: m = 2.5 kg, g = 9.8 N/kg

    W=2.5×9.8W = 2.5 \times 9.8
  3. 3

    Step 3: Calculate result and add correct units

    W=24.5 NW = 24.5 \text{ N}

Exam tip:

Always use the value of g provided in the question; if no value is given, use g = 9.8 N/kg (the value printed on the exam paper's front cover).

2. Density Core Concepts (Core)★★☆☆☆⏱ 5 min

Density describes how much mass is contained in a given volume of a substance. It is an intensive property, meaning it does not depend on the size of the sample of the substance. The SI unit of density is kilograms per cubic metre (kg/m³), but grams per cubic centimetre (g/cm³) is also commonly used in IGCSE problems.

📘 Definition

Density

ρ=mV\rho = \frac{m}{V}

Mass per unit volume of a substance.

Example:

A 10cm³ block of aluminium with mass 27g has a density of 2.7 g/cm³.

📐 Worked Example

A block of iron has a mass of 1580 kg and a volume of 0.2 m³. Calculate the density of iron.

  1. 1

    Step 1: Recall the density formula

    ρ=mV\rho = \frac{m}{V}
  2. 2

    Step 2: Substitute m = 1580 kg, V = 0.2 m³

    ρ=15800.2\rho = \frac{1580}{0.2}
  3. 3

    Step 3: Compute result and add correct units

    ρ=7900 kg/m3\rho = 7900 \text{ kg/m}^3

Exam tip:

Use the conversion factor 1 g/cm³ = 1000 kg/m³ to switch between common density units quickly.

3. Rearranging Core Formulas (Core)★★☆☆☆⏱ 5 min

You will often be asked to rearrange the weight and density formulas to find unknown mass or volume from given values. The formula triangle method is a quick, error-free way to rearrange these equations for any unknown quantity.

📐 Worked Example

A liquid has a density of 0.8 g/cm³. What volume of this liquid has a mass of 120 g?

  1. 1

    Step 1: Rearrange density formula to solve for volume

    V=mρV = \frac{m}{\rho}
  2. 2

    Step 2: Substitute m = 120 g, ρ = 0.8 g/cm³

    V=1200.8V = \frac{120}{0.8}
  3. 3

    Step 3: Calculate result with correct units

    V=150 cm3V = 150 \text{ cm}^3

4. Experimental Determination of Density (Core)★★★☆☆⏱ 7 min

All candidates should be able to describe and carry out experiments to measure the density of regular solids, irregular solids that sink, and liquids. All methods use the density formula, with different techniques to measure mass and volume accurately.

  • Regular solids: Measure mass with a digital balance, measure dimensions with a ruler, calculate volume using geometric formula, compute density.

  • Irregular solids: Measure mass with a digital balance, find volume via water displacement: record initial water volume in a measuring cylinder, submerge the solid, record final volume, the difference is the solid's volume.

  • Liquids: Measure mass of empty beaker, add liquid and measure total mass, subtract empty beaker mass to get liquid mass, measure liquid volume with a measuring cylinder, compute density.

📐 Worked Example

A student measures the density of an irregular stone. They record the mass of the stone as 180 g. The initial volume of water in a measuring cylinder is 40 cm³, and after adding the stone, the volume rises to 100 cm³. Calculate the density of the stone in g/cm³.

  1. 1

    Step 1: Calculate volume of the stone via displacement

    V=10040=60 cm3V = 100 - 40 = 60 \text{ cm}^3
  2. 2

    Step 2: Substitute values into density formula

    ρ=mV=18060\rho = \frac{m}{V} = \frac{180}{60}
  3. 3

    Step 3: Calculate result with units

    ρ=3 g/cm3\rho = 3 \text{ g/cm}^3

Exam tip:

Always mention reading the measuring cylinder at eye level to the meniscus to avoid parallax error when describing density experiments for marks.

5. Predicting Floating and Sinking from Density (Extended only)★★★☆☆Extended only⏱ 5 min

Extended candidates use density data to predict whether an object floats or sinks in a liquid, and whether one liquid floats on top of another. An object floats in a liquid if its density is less than the density of the liquid, and sinks if its density is greater than the density of the liquid.

  • Object in a liquid: Compare the density of the object with the density of the liquid. Less dense than the liquid = floats; more dense = sinks.

  • Two liquids that do not mix (immiscible): The less dense liquid floats on top of the denser liquid, forming separate layers with the densest liquid at the bottom.

📐 Worked Example

Oil has a density of 0.92 g/cm³, water has a density of 1.0 g/cm³, and a plastic bead has a density of 0.95 g/cm³. The oil and water do not mix. Describe what happens when the oil, water and bead are placed together in a beaker.

  1. 1

    Step 1: Compare the two liquids. Oil (0.92 g/cm³) is less dense than water (1.0 g/cm³), so the oil floats and forms a layer on top of the water.

  2. 2

    Step 2: Compare the bead with each liquid. The bead (0.95 g/cm³) is more dense than the oil (0.92 g/cm³) but less dense than the water (1.0 g/cm³).

  3. 3

    Step 3: Conclude the bead sinks through the oil layer but floats on the water, resting at the boundary between the oil and water layers.

Exam tip:

For floating questions, always compare density values directly: less dense floats, more dense sinks. State the comparison explicitly to earn the mark.

6. Common Pitfalls

Wrong move:

Claiming mass changes when an object is taken to the moon

Why:

Mass is a measure of matter, which is constant for an object regardless of location; only weight changes with gravitational field strength.

Correct move:

State mass is constant, while weight on the moon is 1/6 of its value on Earth.

Wrong move:

Using mismatched units in density calculations, e.g. mass in grams and volume in m³

Why:

Unit mismatch gives an incorrect density value by a factor of 1,000 or more.

Correct move:

Use consistent units: kg and m³ for kg/m³, g and cm³ for g/cm³, convert units before calculating if needed.

Wrong move:

Forgetting to subtract the mass of the empty beaker when measuring liquid mass (Extended)

Why:

This overestimates the mass of the liquid, leading to an incorrectly high calculated density.

Correct move:

Measure the mass of the empty beaker first, subtract this from the total mass of beaker + liquid to get the true liquid mass.

Wrong move:

Stating density in g/cm³ when the question asks for SI units

Why:

The SI unit of density is kg/m³, g/cm³ is a non-SI common unit.

Correct move:

Convert g/cm³ to kg/m³ by multiplying by 1000 when SI units are requested.

7. Quick Reference Cheatsheet

Quantity

Symbol

SI Unit

Formula/Method

Tier

Mass

m

Kilogram (kg)

Both

Weight

W

Newton (N)

W = m × g

Both

Density

ρ

kg/m³

ρ = m / V

Both

Regular solid density

kg/m³

Calculate volume via dimensions

Core

Irregular solid density

kg/m³

Measure volume via displacement

Core

Liquid density

kg/m³

Subtract empty beaker mass for liquid mass

Core

Floating / immiscible liquids

Compare densities: less dense floats, more dense sinks

Extended

8. Frequently Asked

What is the difference between mass and weight?

Mass is the amount of matter in an object, measured in kg, and is constant everywhere. Weight is the gravitational force on an object, measured in N, and changes depending on the local gravitational field strength.

What value of g should I use for CIE IGCSE Physics 0625 calculations?

Always use the value given in the question. If no value is provided, use g = 9.8 N/kg, the value printed on the front cover of every 0625 exam paper ("take the weight of 1.0 kg to be 9.8 N").

How do I convert between g/cm³ and kg/m³?

1 g/cm³ = 1000 kg/m³. Multiply a density in g/cm³ by 1000 to get the value in kg/m³, divide by 1000 to convert from kg/m³ to g/cm³.

Going deeper

What's Next

Now that you have mastered mass, weight and density for CIE IGCSE Physics 0625, you can move on to related topics in the Motion, Forces and Energy unit. Next, you will learn about effects of forces including Hooke’s Law for springs, which builds on your understanding of forces measured in newtons. Practise describing density experiments carefully, as density determination is commonly assessed in the practical papers (Paper 5 or Paper 6). Make sure you memorize the core formulas for weight and density, as they appear regularly across all papers in both calculation and definition questions. Practice rearranging these formulas for different unknown quantities to build speed for your exam.